-n-2(2n+4)+4=-9+4(2n+1)

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Solution for -n-2(2n+4)+4=-9+4(2n+1) equation: 



-n-2(2n+4)+4=-9+4(2n+1)

We move all terms to the left:

-n-2(2n+4)+4-(-9+4(2n+1))=0

We add all the numbers together, and all the variables

-1n-2(2n+4)-(-9+4(2n+1))+4=0

We multiply parentheses

-1n-4n-(-9+4(2n+1))-8+4=0



We calculate terms in parentheses: -(-9+4(2n+1)), so:

-9+4(2n+1)

determiningTheFunctionDomain
4(2n+1)-9

We multiply parentheses

8n+4-9

We add all the numbers together, and all the variables

8n-5

Back to the equation:

-(8n-5)



We add all the numbers together, and all the variables

-5n-(8n-5)-4=0

We get rid of parentheses

-5n-8n+5-4=0

We add all the numbers together, and all the variables

-13n+1=0

We move all terms containing n to the left, all other terms to the right

-13n=-1

n=-1/-13

n=1/13

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