(X-5)+(3x+7)+(6x-10)=108

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Solution for (X-5)+(3x+7)+(6x-10)=108 equation: 



(X-5)+(3X+7)+(6X-10)=108

We move all terms to the left:

(X-5)+(3X+7)+(6X-10)-(108)=0

We get rid of parentheses

X+3X+6X-5+7-10-108=0

We add all the numbers together, and all the variables

10X-116=0

We move all terms containing X to the left, all other terms to the right

10X=116

X=116/10

X=11+3/5

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