z/2+(80-z)=64

Solution for z/2+(80-z)=64 equation:

z/2+(80-z)=64

We move all terms to the left:

z/2+(80-z)-(64)=0

We add all the numbers together, and all the variables

z/2+(-1z+80)-64=0

We get rid of parentheses

z/2-1z+80-64=0

We multiply all the terms by the denominator


z-1z*2+80*2-64*2=0

We add all the numbers together, and all the variables

z-1z*2+32=0

Wy multiply elements

z-2z+32=0

We add all the numbers together, and all the variables

-1z+32=0

We move all terms containing z to the left, all other terms to the right

-z=-32

z=-32/-1

z=+32