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7x+5(x-3)=5(x+4)-3x
We move all terms to the left:
7x+5(x-3)-(5(x+4)-3x)=0
We multiply parentheses
7x+5x-(5(x+4)-3x)-15=0
We calculate terms in parentheses: -(5(x+4)-3x), so:We add all the numbers together, and all the variables
5(x+4)-3x
We add all the numbers together, and all the variables
-3x+5(x+4)
We multiply parentheses
-3x+5x+20
We add all the numbers together, and all the variables
2x+20
Back to the equation:
-(2x+20)
12x-(2x+20)-15=0
We get rid of parentheses
12x-2x-20-15=0
We add all the numbers together, and all the variables
10x-35=0
We move all terms containing x to the left, all other terms to the right
10x=35
x=35/10
x=3+1/2
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