180=(x+4)+(3x+4)+(2x+4)

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Solution for 180=(x+4)+(3x+4)+(2x+4) equation: 



180=(x+4)+(3x+4)+(2x+4)

We move all terms to the left:

180-((x+4)+(3x+4)+(2x+4))=0



We calculate terms in parentheses: -((x+4)+(3x+4)+(2x+4)), so:

(x+4)+(3x+4)+(2x+4)

We get rid of parentheses

x+3x+2x+4+4+4

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

-6x-12+180=0

We add all the numbers together, and all the variables

-6x+168=0

We move all terms containing x to the left, all other terms to the right

-6x=-168

x=-168/-6

x=+28

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