y2+24y=25

Solution for y2+24y=25 equation:

y2+24y=25

We move all terms to the left:

y2+24y-(25)=0

We add all the numbers together, and all the variables

y^2+24y-25=0

a = 1; b = 24; c = -25;
Δ = b2-4ac
Δ = 242-4·1·(-25)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-26}{2*1}=\frac{-50}{2}
=-25
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+26}{2*1}=\frac{2}{2}
=1
$