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(x-35)=(2x+1)
We move all terms to the left:
(x-35)-((2x+1))=0
We get rid of parentheses
x-((2x+1))-35=0
We calculate terms in parentheses: -((2x+1)), so:We get rid of parentheses
(2x+1)
We get rid of parentheses
2x+1
Back to the equation:
-(2x+1)
x-2x-1-35=0
We add all the numbers together, and all the variables
-1x-36=0
We move all terms containing x to the left, all other terms to the right
-x=36
x=36/-1
x=-36
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