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(9c-5)(3c-5)=0
We multiply parentheses ..
(+27c^2-45c-15c+25)=0
We get rid of parentheses
27c^2-45c-15c+25=0
We add all the numbers together, and all the variables
27c^2-60c+25=0
a = 27; b = -60; c = +25;
Δ = b2-4ac
Δ = -602-4·27·25
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30}{2*27}=\frac{30}{54} =5/9 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30}{2*27}=\frac{90}{54} =1+2/3 $
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