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y-3/4y=11
We move all terms to the left:
y-3/4y-(11)=0
Domain of the equation: 4y!=0We multiply all the terms by the denominator
y!=0/4
y!=0
y∈R
y*4y-11*4y-3=0
Wy multiply elements
4y^2-44y-3=0
a = 4; b = -44; c = -3;
Δ = b2-4ac
Δ = -442-4·4·(-3)
Δ = 1984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1984}=\sqrt{64*31}=\sqrt{64}*\sqrt{31}=8\sqrt{31}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-8\sqrt{31}}{2*4}=\frac{44-8\sqrt{31}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+8\sqrt{31}}{2*4}=\frac{44+8\sqrt{31}}{8} $
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