4(3y-5)=-2(-y+8)-6y

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Solution for 4(3y-5)=-2(-y+8)-6y equation: 



4(3y-5)=-2(-y+8)-6y

We move all terms to the left:

4(3y-5)-(-2(-y+8)-6y)=0

We add all the numbers together, and all the variables

4(3y-5)-(-2(-1y+8)-6y)=0

We multiply parentheses

12y-(-2(-1y+8)-6y)-20=0



We calculate terms in parentheses: -(-2(-1y+8)-6y), so:

-2(-1y+8)-6y

We add all the numbers together, and all the variables

-6y-2(-1y+8)

We multiply parentheses

-6y+2y-16

We add all the numbers together, and all the variables

-4y-16

Back to the equation:

-(-4y-16)



We get rid of parentheses

12y+4y+16-20=0

We add all the numbers together, and all the variables

16y-4=0

We move all terms containing y to the left, all other terms to the right

16y=4

y=4/16

y=1/4

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