20=4(j+1)

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Solution for 20=4(j+1) equation: 



20=4(j+1)

We move all terms to the left:

20-(4(j+1))=0



We calculate terms in parentheses: -(4(j+1)), so:

4(j+1)

We multiply parentheses

4j+4

Back to the equation:

-(4j+4)



We get rid of parentheses

-4j-4+20=0

We add all the numbers together, and all the variables

-4j+16=0

We move all terms containing j to the left, all other terms to the right

-4j=-16

j=-16/-4

j=+4

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