y+(y+3)+(2y-5)=10

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Solution for y+(y+3)+(2y-5)=10 equation: 



y+(y+3)+(2y-5)=10

We move all terms to the left:

y+(y+3)+(2y-5)-(10)=0

We get rid of parentheses

y+y+2y+3-5-10=0

We add all the numbers together, and all the variables

4y-12=0

We move all terms containing y to the left, all other terms to the right

4y=12

y=12/4

y=3

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