x=4x2+40x+64

Solution for x=4x2+40x+64 equation:

x=4x^2+40x+64

We move all terms to the left:

x-(4x^2+40x+64)=0

We get rid of parentheses

-4x^2+x-40x-64=0

We add all the numbers together, and all the variables

-4x^2-39x-64=0

a = -4; b = -39; c = -64;
Δ = b2-4ac
Δ = -392-4·(-4)·(-64)
Δ = 497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-\sqrt{497}}{2*-4}=\frac{39-\sqrt{497}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+\sqrt{497}}{2*-4}=\frac{39+\sqrt{497}}{-8}
$