3(q-6)=4(q-2)

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Solution for 3(q-6)=4(q-2) equation: 



3(q-6)=4(q-2)

We move all terms to the left:

3(q-6)-(4(q-2))=0

We multiply parentheses

3q-(4(q-2))-18=0



We calculate terms in parentheses: -(4(q-2)), so:

4(q-2)

We multiply parentheses

4q-8

Back to the equation:

-(4q-8)



We get rid of parentheses

3q-4q+8-18=0

We add all the numbers together, and all the variables

-1q-10=0

We move all terms containing q to the left, all other terms to the right

-q=10

q=10/-1

q=-10

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