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x=100-2x-(2x+x)
We move all terms to the left:
x-(100-2x-(2x+x))=0
We add all the numbers together, and all the variables
x-(100-2x-(+3x))=0
We calculate terms in parentheses: -(100-2x-(+3x)), so:We get rid of parentheses
100-2x-(+3x)
determiningTheFunctionDomain -2x-(+3x)+100
We get rid of parentheses
-2x-3x+100
We add all the numbers together, and all the variables
-5x+100
Back to the equation:
-(-5x+100)
x+5x-100=0
We add all the numbers together, and all the variables
6x-100=0
We move all terms containing x to the left, all other terms to the right
6x=100
x=100/6
x=16+2/3
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