-7x-(2/5)x=0

Solution for -7x-(2/5)x=0 equation:

-7x-(2/5)x=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-7x-(+2/5)x=0

We multiply parentheses

-2x^2-7x=0

a = -2; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-2)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-2}=\frac{0}{-4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-2}=\frac{14}{-4}
=-3+1/2
$