x-5=2(x+1)-3(4x-5)

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Solution for x-5=2(x+1)-3(4x-5) equation: 



x-5=2(x+1)-3(4x-5)

We move all terms to the left:

x-5-(2(x+1)-3(4x-5))=0



We calculate terms in parentheses: -(2(x+1)-3(4x-5)), so:

2(x+1)-3(4x-5)

We multiply parentheses

2x-12x+2+15

We add all the numbers together, and all the variables

-10x+17

Back to the equation:

-(-10x+17)



We get rid of parentheses

x+10x-17-5=0

We add all the numbers together, and all the variables

11x-22=0

We move all terms containing x to the left, all other terms to the right

11x=22

x=22/11

x=2

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