(17/2)p=10

Solution for (17/2)p=10 equation:

(17/2)p=10

We move all terms to the left:

(17/2)p-(10)=0


Domain of the equation: 2)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(+17/2)p-10=0

We multiply parentheses

17p^2-10=0

a = 17; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·17·(-10)
Δ = 680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{680}=\sqrt{4*170}=\sqrt{4}*\sqrt{170}=2\sqrt{170}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{170}}{2*17}=\frac{0-2\sqrt{170}}{34}
=-\frac{2\sqrt{170}}{34}
=-\frac{\sqrt{170}}{17}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{170}}{2*17}=\frac{0+2\sqrt{170}}{34}
=\frac{2\sqrt{170}}{34}
=\frac{\sqrt{170}}{17}
$