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x=-1/3x+9
We move all terms to the left:
x-(-1/3x+9)=0
Domain of the equation: 3x+9)!=0We get rid of parentheses
x∈R
x+1/3x-9=0
We multiply all the terms by the denominator
x*3x-9*3x+1=0
Wy multiply elements
3x^2-27x+1=0
a = 3; b = -27; c = +1;
Δ = b2-4ac
Δ = -272-4·3·1
Δ = 717
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{717}}{2*3}=\frac{27-\sqrt{717}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{717}}{2*3}=\frac{27+\sqrt{717}}{6} $
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