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X(X-3)=X(X-4)+2
We move all terms to the left:
X(X-3)-(X(X-4)+2)=0
We multiply parentheses
X^2-3X-(X(X-4)+2)=0
We calculate terms in parentheses: -(X(X-4)+2), so:We get rid of parentheses
X(X-4)+2
We multiply parentheses
X^2-4X+2
Back to the equation:
-(X^2-4X+2)
X^2-X^2-3X+4X-2=0
We add all the numbers together, and all the variables
X-2=0
We move all terms containing X to the left, all other terms to the right
X=2
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