x2=(x+3)(x-3)+9

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Solution for x2=(x+3)(x-3)+9 equation:



x2=(x+3)(x-3)+9
We move all terms to the left:
x2-((x+3)(x-3)+9)=0
We add all the numbers together, and all the variables
x^2-((x+3)(x-3)+9)=0
We use the square of the difference formula
x^2+x^2+9=0
We add all the numbers together, and all the variables
2x^2+9=0
a = 2; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·2·9
Δ = -72
Delta is less than zero, so there is no solution for the equation

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