(2/3)(6a+9)=20.4

Solution for (2/3)(6a+9)=20.4 equation:

(2/3)(6a+9)=20.4

We move all terms to the left:

(2/3)(6a+9)-(20.4)=0


Domain of the equation: 3)(6a+9)!=0

a∈R


We add all the numbers together, and all the variables

(+2/3)(6a+9)-(20.4)=0

We add all the numbers together, and all the variables

(+2/3)(6a+9)-20.4=0

We multiply parentheses ..

(+12a^2+2/3*9)-20.4=0

We multiply all the terms by the denominator


(+12a^2+2-(20.4)*3*9)=0


We calculate terms in parentheses: +(+12a^2+2-(20.4)*3*9), so:

+12a^2+2-(20.4)*3*9

determiningTheFunctionDomain
12a^2+2-(20.4)*3*9

We add all the numbers together, and all the variables

12a^2-548.8

Back to the equation:

+(12a^2-548.8)


We get rid of parentheses

12a^2-548.8=0

a = 12; b = 0; c = -548.8;
Δ = b2-4ac
Δ = 02-4·12·(-548.8)
Δ = 26342.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{26342.4}}{2*12}=\frac{0-\sqrt{26342.4}}{24}
=-\frac{\sqrt{}}{24}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{26342.4}}{2*12}=\frac{0+\sqrt{26342.4}}{24}
=\frac{\sqrt{}}{24}
$