x2-4x+4=4x2-16x+16

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Solution for x2-4x+4=4x2-16x+16 equation: 



x2-4x+4=4x^2-16x+16

We move all terms to the left:

x2-4x+4-(4x^2-16x+16)=0

We add all the numbers together, and all the variables

x^2-4x-(4x^2-16x+16)+4=0

We get rid of parentheses

x^2-4x^2-4x+16x-16+4=0

We add all the numbers together, and all the variables

-3x^2+12x-12=0

a = -3; b = 12; c = -12;
Δ = b2-4ac
Δ = 122-4·(-3)·(-12)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{-6}=+2$

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