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3x=1/2(6x)
We move all terms to the left:
3x-(1/2(6x))=0
Domain of the equation: 26x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+1/26x)=0
We get rid of parentheses
3x-1/26x=0
We multiply all the terms by the denominator
3x*26x-1=0
Wy multiply elements
78x^2-1=0
a = 78; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·78·(-1)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{78}}{2*78}=\frac{0-2\sqrt{78}}{156} =-\frac{2\sqrt{78}}{156} =-\frac{\sqrt{78}}{78} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{78}}{2*78}=\frac{0+2\sqrt{78}}{156} =\frac{2\sqrt{78}}{156} =\frac{\sqrt{78}}{78} $
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