(2x=3)+(x-6)=90

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Solution for (2x=3)+(x-6)=90 equation: 



(2x=3)+(x-6)=90

We move all terms to the left:

(2x-(3)+(x-6))=0



We calculate terms in parentheses: +(2x-3+(x-6)), so:

2x-3+(x-6)

determiningTheFunctionDomain
2x+(x-6)-3

We get rid of parentheses

2x+x-6-3

We add all the numbers together, and all the variables

3x-9

Back to the equation:

+(3x-9)



We get rid of parentheses

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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