2(5y-5)+3=3(6y+1)+17

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Solution for 2(5y-5)+3=3(6y+1)+17 equation: 



2(5y-5)+3=3(6y+1)+17

We move all terms to the left:

2(5y-5)+3-(3(6y+1)+17)=0

We multiply parentheses

10y-(3(6y+1)+17)-10+3=0



We calculate terms in parentheses: -(3(6y+1)+17), so:

3(6y+1)+17

We multiply parentheses

18y+3+17

We add all the numbers together, and all the variables

18y+20

Back to the equation:

-(18y+20)



We add all the numbers together, and all the variables

10y-(18y+20)-7=0

We get rid of parentheses

10y-18y-20-7=0

We add all the numbers together, and all the variables

-8y-27=0

We move all terms containing y to the left, all other terms to the right

-8y=27

y=27/-8

y=-3+3/8

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