x2-41x+210=0

Solution for x2-41x+210=0 equation:

x2-41x+210=0

We add all the numbers together, and all the variables

x^2-41x+210=0

a = 1; b = -41; c = +210;
Δ = b2-4ac
Δ = -412-4·1·210
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-29}{2*1}=\frac{12}{2}
=6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+29}{2*1}=\frac{70}{2}
=35
$