x2-19x=5x-144

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Solution for x2-19x=5x-144 equation: 



x2-19x=5x-144

We move all terms to the left:

x2-19x-(5x-144)=0

We add all the numbers together, and all the variables

x^2-19x-(5x-144)=0

We get rid of parentheses

x^2-19x-5x+144=0

We add all the numbers together, and all the variables

x^2-24x+144=0

a = 1; b = -24; c = +144;
Δ = b2-4ac
Δ = -242-4·1·144
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{24}{2}=12$

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