5(v+1)=3(2v-1)

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Solution for 5(v+1)=3(2v-1) equation:



5(v+1)=3(2v-1)
We move all terms to the left:
5(v+1)-(3(2v-1))=0
We multiply parentheses
5v-(3(2v-1))+5=0
We calculate terms in parentheses: -(3(2v-1)), so:
3(2v-1)
We multiply parentheses
6v-3
Back to the equation:
-(6v-3)
We get rid of parentheses
5v-6v+3+5=0
We add all the numbers together, and all the variables
-1v+8=0
We move all terms containing v to the left, all other terms to the right
-v=-8
v=-8/-1
v=+8

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