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x2-10x-31=0
We add all the numbers together, and all the variables
x^2-10x-31=0
a = 1; b = -10; c = -31;
Δ = b2-4ac
Δ = -102-4·1·(-31)
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{14}}{2*1}=\frac{10-4\sqrt{14}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{14}}{2*1}=\frac{10+4\sqrt{14}}{2} $
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