1/2(2y+3)=2y+1

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Solution for 1/2(2y+3)=2y+1 equation: 



1/2(2y+3)=2y+1

We move all terms to the left:

1/2(2y+3)-(2y+1)=0



Domain of the equation: 2(2y+3)!=0

y∈R



We get rid of parentheses

1/2(2y+3)-2y-1=0

We multiply all the terms by the denominator


-2y*2(2y+3)-1*2(2y+3)+1=0

Wy multiply elements

-4y^2(2-2y(2+1=0

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