-3=1/2(-6)+b

Solution for -3=1/2(-6)+b equation:

-3=1/2(-6)+b

We move all terms to the left:

-3-(1/2(-6)+b)=0


Domain of the equation: 2(-6)+b)!=0

b∈R


We multiply all the terms by the denominator


-(1-3*2(-6)+b)=0


We calculate terms in parentheses: -(1-3*2(-6)+b), so:

1-3*2(-6)+b

determiningTheFunctionDomain
b+1-3*2(-6)

We add all the numbers together, and all the variables

b+37

Back to the equation:

-(b+37)


We get rid of parentheses

-b-37=0

We add all the numbers together, and all the variables

-1b-37=0

We move all terms containing b to the left, all other terms to the right

-b=37

b=37/-1

b=-37