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x2+31x+58=0
We add all the numbers together, and all the variables
x^2+31x+58=0
a = 1; b = 31; c = +58;
Δ = b2-4ac
Δ = 312-4·1·58
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-27}{2*1}=\frac{-58}{2} =-29 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+27}{2*1}=\frac{-4}{2} =-2 $
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