0.002(5-k)+0.07(k-4)=1

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Solution for 0.002(5-k)+0.07(k-4)=1 equation: 



0.002(5-k)+0.07(k-4)=1

We move all terms to the left:

0.002(5-k)+0.07(k-4)-(1)=0

We add all the numbers together, and all the variables

0.002(-1k+5)+0.07(k-4)-1=0

We multiply parentheses

-0.002k+0.07k+0.01-0.28-1=0

We add all the numbers together, and all the variables

0.068k-1.27=0

We move all terms containing k to the left, all other terms to the right

0.068k=1.27

k=1.27/0.068

k=18+0.046/0.068

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