4(x-3)=2(x+1)+4

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Solution for 4(x-3)=2(x+1)+4 equation: 



4(x-3)=2(x+1)+4

We move all terms to the left:

4(x-3)-(2(x+1)+4)=0

We multiply parentheses

4x-(2(x+1)+4)-12=0



We calculate terms in parentheses: -(2(x+1)+4), so:

2(x+1)+4

We multiply parentheses

2x+2+4

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

4x-2x-6-12=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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