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X+6+2=2/3X
We move all terms to the left:
X+6+2-(2/3X)=0
Domain of the equation: 3X)!=0We add all the numbers together, and all the variables
X!=0/1
X!=0
X∈R
X-(+2/3X)+6+2=0
We add all the numbers together, and all the variables
X-(+2/3X)+8=0
We get rid of parentheses
X-2/3X+8=0
We multiply all the terms by the denominator
X*3X+8*3X-2=0
Wy multiply elements
3X^2+24X-2=0
a = 3; b = 24; c = -2;
Δ = b2-4ac
Δ = 242-4·3·(-2)
Δ = 600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{600}=\sqrt{100*6}=\sqrt{100}*\sqrt{6}=10\sqrt{6}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-10\sqrt{6}}{2*3}=\frac{-24-10\sqrt{6}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+10\sqrt{6}}{2*3}=\frac{-24+10\sqrt{6}}{6} $
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