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x2+15x=1008
We move all terms to the left:
x2+15x-(1008)=0
We add all the numbers together, and all the variables
x^2+15x-1008=0
a = 1; b = 15; c = -1008;
Δ = b2-4ac
Δ = 152-4·1·(-1008)
Δ = 4257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4257}=\sqrt{9*473}=\sqrt{9}*\sqrt{473}=3\sqrt{473}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3\sqrt{473}}{2*1}=\frac{-15-3\sqrt{473}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3\sqrt{473}}{2*1}=\frac{-15+3\sqrt{473}}{2} $
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