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7(x+4)=5(x+5)+6
We move all terms to the left:
7(x+4)-(5(x+5)+6)=0
We multiply parentheses
7x-(5(x+5)+6)+28=0
We calculate terms in parentheses: -(5(x+5)+6), so:We get rid of parentheses
5(x+5)+6
We multiply parentheses
5x+25+6
We add all the numbers together, and all the variables
5x+31
Back to the equation:
-(5x+31)
7x-5x-31+28=0
We add all the numbers together, and all the variables
2x-3=0
We move all terms containing x to the left, all other terms to the right
2x=3
x=3/2
x=1+1/2
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