2(x+8)-9/3=5-(1-3x)/4

Solution for 2(x+8)-9/3=5-(1-3x)/4 equation:

2(x+8)-9/3=5-(1-3x)/4

We move all terms to the left:

2(x+8)-9/3-(5-(1-3x)/4)=0

We add all the numbers together, and all the variables

2(x+8)-(5-(-3x+1)/4)-9/3=0

We add all the numbers together, and all the variables

2(x+8)-(5-(-3x+1)/4)-3=0

We multiply parentheses

2x-(5-(-3x+1)/4)+16-3=0

We multiply all the terms by the denominator


2x*4)-(5-(-3x+1)+16*4)-3*4)=0

We add all the numbers together, and all the variables

2x*4)-(5-(-3x+1)=0

Wy multiply elements

8x^2-(-3x+1)=0

We get rid of parentheses

8x^2+3x-1=0

a = 8; b = 3; c = -1;
Δ = b2-4ac
Δ = 32-4·8·(-1)
Δ = 41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{41}}{2*8}=\frac{-3-\sqrt{41}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{41}}{2*8}=\frac{-3+\sqrt{41}}{16}
$