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x2+15x+44=0
We add all the numbers together, and all the variables
x^2+15x+44=0
a = 1; b = 15; c = +44;
Δ = b2-4ac
Δ = 152-4·1·44
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-7}{2*1}=\frac{-22}{2} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+7}{2*1}=\frac{-8}{2} =-4 $
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