((1.28+.8x)/1.28)+((3.36+.1x)/3.36)=1

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Solution for ((1.28+.8x)/1.28)+((3.36+.1x)/3.36)=1 equation: 



((1.28+.8x)/1.28)+((3.36+.1x)/3.36)=1

We move all terms to the left:

((1.28+.8x)/1.28)+((3.36+.1x)/3.36)-(1)=0

We add all the numbers together, and all the variables

((.8x+1.28)/1.28)+((.1x+3.36)/3.36)-1=0

We calculate fractions


(3.36x+4.3008)/()+(1.28x+4.3008)/()-1=0

We multiply all the terms by the denominator


(3.36x+4.3008)+(1.28x+4.3008)-1*()=0

We add all the numbers together, and all the variables

(3.36x+4.3008)+(1.28x+4.3008)=0

We get rid of parentheses

3.36x+1.28x+4.3008+4.3008=0

We add all the numbers together, and all the variables

4.64x+8.6016=0

We move all terms containing x to the left, all other terms to the right

4.64x=-8.6016

x=-8.6016/4.64

x=-1+2.0195758564437/2.3654159869494

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