12-5(3-2x)=8x-3(x+1)

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Solution for 12-5(3-2x)=8x-3(x+1) equation: 



12-5(3-2x)=8x-3(x+1)

We move all terms to the left:

12-5(3-2x)-(8x-3(x+1))=0

We add all the numbers together, and all the variables

-5(-2x+3)-(8x-3(x+1))+12=0

We multiply parentheses

10x-(8x-3(x+1))-15+12=0



We calculate terms in parentheses: -(8x-3(x+1)), so:

8x-3(x+1)

We multiply parentheses

8x-3x-3

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We add all the numbers together, and all the variables

10x-(5x-3)-3=0

We get rid of parentheses

10x-5x+3-3=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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