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x/5+2x=6/5x+10
We move all terms to the left:
x/5+2x-(6/5x+10)=0
Domain of the equation: 5x+10)!=0We add all the numbers together, and all the variables
x∈R
2x+x/5-(6/5x+10)=0
We get rid of parentheses
2x+x/5-6/5x-10=0
We calculate fractions
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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