(2x-1)(x+10)=-34

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Solution for (2x-1)(x+10)=-34 equation:



(2x-1)(x+10)=-34
We move all terms to the left:
(2x-1)(x+10)-(-34)=0
We add all the numbers together, and all the variables
(2x-1)(x+10)+34=0
We multiply parentheses ..
(+2x^2+20x-1x-10)+34=0
We get rid of parentheses
2x^2+20x-1x-10+34=0
We add all the numbers together, and all the variables
2x^2+19x+24=0
a = 2; b = 19; c = +24;
Δ = b2-4ac
Δ = 192-4·2·24
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-13}{2*2}=\frac{-32}{4} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+13}{2*2}=\frac{-6}{4} =-1+1/2 $

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