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1/2(3x-16)=4/5(x+3.4)
We move all terms to the left:
1/2(3x-16)-(4/5(x+3.4))=0
Domain of the equation: 2(3x-16)!=0
x∈R
Domain of the equation: 5(x+3.4))!=0We calculate fractions
x∈R
(5xx/(2(3x-16)*5(x+3.4)))+(-8x3/(2(3x-16)*5(x+3.4)))=0
We calculate terms in parentheses: +(5xx/(2(3x-16)*5(x+3.4))), so:
5xx/(2(3x-16)*5(x+3.4))
We multiply all the terms by the denominator
5xx
Back to the equation:
+(5xx)
We calculate terms in parentheses: +(-8x3/(2(3x-16)*5(x+3.4))), so:
-8x3/(2(3x-16)*5(x+3.4))
We multiply all the terms by the denominator
-8x3
We add all the numbers together, and all the variables
-8x^3
We do not support expression: x^3
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