3(3b-7)+15=9b-6

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Solution for 3(3b-7)+15=9b-6 equation: 



3(3b-7)+15=9b-6

We move all terms to the left:

3(3b-7)+15-(9b-6)=0

We multiply parentheses

9b-(9b-6)-21+15=0

We get rid of parentheses

9b-9b+6-21+15=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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