If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/2x+2=2x-1
We move all terms to the left:
1/2x+2-(2x-1)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-2x+1+2=0
We multiply all the terms by the denominator
-2x*2x+1*2x+2*2x+1=0
Wy multiply elements
-4x^2+2x+4x+1=0
We add all the numbers together, and all the variables
-4x^2+6x+1=0
a = -4; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·(-4)·1
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{13}}{2*-4}=\frac{-6-2\sqrt{13}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{13}}{2*-4}=\frac{-6+2\sqrt{13}}{-8} $
| 2(f-6=-16 | | 10(s-5)=-106 | | 8x-2-2x=-6+6x+14 | | n^2+6=10n | | 2x/x+2=2/3 | | 5p+7=3(4-p( | | 2(3s+7)=32 | | 4(2s+9)=76 | | 22x-9=11(2x-3) | | x=x^2-4x^2+8x-20 | | y+2=y+2 | | 24=n/10+32 | | y+2=y-2 | | -17+m/8=13 | | 9y2=y | | 4x+2x=-11 | | 2z+8=6z+12 | | 2x-142+x+16=360 | | 16+8x-25=-7(3-x)=3x | | (q-3)*5=25 | | 4/3x+9=3 | | 5n^2+n=120 | | (x+42)+(2x+1)=360 | | 3j(j-2)=2(j-2) | | F(n)=(-1)n×3 | | 4x+28=62+2x | | 10x+x^2=80 | | X/2-y/0=1/0 | | H=20+60t-16t^2 | | 4x28=62+2x | | 4v^2-5v-17=7 | | 88=-u+282 |