x-9=2x(x-3)+12

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Solution for x-9=2x(x-3)+12 equation: 



x-9=2x(x-3)+12

We move all terms to the left:

x-9-(2x(x-3)+12)=0



We calculate terms in parentheses: -(2x(x-3)+12), so:

2x(x-3)+12

We multiply parentheses

2x^2-6x+12

Back to the equation:

-(2x^2-6x+12)



We get rid of parentheses

-2x^2+x+6x-12-9=0

We add all the numbers together, and all the variables

-2x^2+7x-21=0

a = -2; b = 7; c = -21;
Δ = b2-4ac
Δ = 72-4·(-2)·(-21)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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