J(-28)=1-(2x-9)

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Solution for J(-28)=1-(2x-9) equation: 



(-28)=1-(2J-9)

We move all terms to the left:

(-28)-(1-(2J-9))=0

We add all the numbers together, and all the variables

-(1-(2J-9))-28=0



We calculate terms in parentheses: -(1-(2J-9)), so:

1-(2J-9)

determiningTheFunctionDomain
-(2J-9)+1

We get rid of parentheses

-2J+9+1

We add all the numbers together, and all the variables

-2J+10

Back to the equation:

-(-2J+10)



We get rid of parentheses

2J-10-28=0

We add all the numbers together, and all the variables

2J-38=0

We move all terms containing J to the left, all other terms to the right

2J=38

J=38/2

J=19

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