1/2(6x-4)+2=1/4(20x+8)

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Solution for 1/2(6x-4)+2=1/4(20x+8) equation: 



1/2(6x-4)+2=1/4(20x+8)

We move all terms to the left:

1/2(6x-4)+2-(1/4(20x+8))=0



Domain of the equation: 2(6x-4)!=0

x∈R





Domain of the equation: 4(20x+8))!=0

x∈R



We calculate fractions


(4x2/(2(6x-4)*4(20x+8)))+(-2x6/(2(6x-4)*4(20x+8)))+2=0



We calculate terms in parentheses: +(4x2/(2(6x-4)*4(20x+8))), so:

4x2/(2(6x-4)*4(20x+8))

We multiply all the terms by the denominator


4x2

We add all the numbers together, and all the variables

4x^2

Back to the equation:

+(4x^2)





We calculate terms in parentheses: +(-2x6/(2(6x-4)*4(20x+8))), so:

-2x6/(2(6x-4)*4(20x+8))

We multiply all the terms by the denominator


-2x6

We add all the numbers together, and all the variables

-2x^6

We do not support expression: x^6

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